Problem
A ladder of mass and length leans against a smooth vertical wall (no friction). The ladder makes an angle of with the floor. The coefficient of static friction between ladder and floor is . Does the ladder slip?
Solution
Step 1 — Forces on the ladder.
- weight , applied at the ladder’s centre;
- floor reaction , vertical, applied at the foot;
- friction at the floor , horizontal, applied at the foot;
- wall reaction , horizontal (the wall is smooth, no friction), applied at the top end.
Step 2 — Translational equilibrium :
Step 3 — Rotational equilibrium (clever pole at the foot). Choosing the pole at the foot of the ladder, and have zero lever arm and vanish. What remains is the weight (horizontal arm ) and the wall reaction (applied at the top, height ):
Step 4 — Comparison with maximum friction. From , while the available static friction is
Since , the required friction is amply available:
Linked atoms
Argomenti: Statics and equilibrium Concetti: Static equilibrium · Moment of a force · Static friction · Normal force · Weight force Competenze: Moment balance · Choice of pole · Vector decomposition Metodi: Decomposition into Cartesian components Oggetti: Rigid body · Rod