The equations of uniformly accelerated motion extend naturally to the two-dimensional case by replacing scalars with vectors:

Equations of accelerated motion in 2D

SBSA=vA(tBtA)+12a(tBtA)2\vec{S}_B - \vec{S}_A = \vec{v}_A\,(t_B - t_A) + \frac{1}{2}\,\vec{a}\,(t_B - t_A)^2 vBvA=a(tBtA)\vec{v}_B - \vec{v}_A = \vec{a}\,(t_B - t_A)

In components, the equation of motion becomes a pair of independent equations:

{Sx(t)=SA,x+vA,x(ttA)+12ax(ttA)2Sy(t)=SA,y+vA,y(ttA)+12ay(ttA)2\begin{cases} S_x(t) = S_{A,x} + v_{A,x}\,(t - t_A) + \frac{1}{2}\,a_x\,(t-t_A)^2 \\ S_y(t) = S_{A,y} + v_{A,y}\,(t - t_A) + \frac{1}{2}\,a_y\,(t-t_A)^2 \end{cases}

The trajectory of a 2D motion with constant acceleration is a parabola. The most important case is projectile motion (oblique launch), in which the acceleration is entirely vertical, directed downwards:

a=(0g)\vec{a} = \begin{pmatrix} 0 \\ -g \end{pmatrix}

Here lies the key to projectile motion: along xx there is no acceleration, so the horizontal motion is uniform; along yy only gravity acts, so the vertical motion is free fall. The two components are independent and combine into the curved trajectory.

Velocity and acceleration, distinct roles

The velocity vector vA\vec{v}_A is always tangent to the trajectory at point A, while the acceleration vector a\vec{a} “curves” the trajectory, bending it towards itself. In projectile motion g\vec{g} always points downwards, even while the body is rising.

Projectile motion: the velocity v\vec{v} is tangent to the trajectory, gravity g\vec{g} always points downwards.

Try it — interactive simulation

Launch a projectile: set the angle and initial speed, then press play. The horizontal component is uniform, the vertical one accelerated: they stay independent and together give the parabola. Blue arrows: total velocity and its vx, vy components; green arrow: gravity. Range R and maximum height marked in red, axes graduated in metres.

Collegamenti

Argomenti: Vettori Concetti: Moto parabolico · Caduta libera Metodi: Scomposizione in componenti cartesiane

Esercizi collegati: Caduta libera in due dimensioni · Calciatore gittata e altezza massima · Esercizio svolto — Gittata di un proiettile