Problem
A body slides down an inclined plane of angle in the presence of kinetic friction . Writing Newton’s second law along the plane and perpendicular to it, show that the body’s acceleration is . At what minimum angle does the body start to move from rest, in the presence of static friction ?
Solution
Step 1 — Choice of axes. It is convenient to choose inclined axes: the axis along the plane, oriented in the direction of descent, and the axis perpendicular to the plane, pointing outward. With this choice the acceleration has only the component.
Step 2 — Resolving the weight. The weight is vertical. Relative to the inclined axes it resolves into:
- a component along the plane (driving): ;
- a component perpendicular to the plane: .
Step 3 — Equation perpendicular to the plane. The body neither leaves nor sinks into the plane, so :
Step 4 — Kinetic friction force. The body is sliding down, so kinetic friction is directed up along the plane (opposing the motion) and has magnitude
Step 5 — Equation along the plane. Along , driving force minus friction equals mass times acceleration:
Dividing by , the mass cancels:
as required.
Step 6 — Minimum angle for slipping. At rest, static friction acts, and it can rise up to . The body starts to move when the driving component exceeds the maximum static friction:
The minimum angle is therefore the one for which :
Links
Topics: Friction Concepts: Newton’s second law · Kinetic friction Skills: Resolving forces on an inclined plane Objects: Inclined plane