Problem
An Atwood machine has and , an ideal pulley and an ideal string. At a certain instant an ant of mass crawls from to . Calculate the percentage change in the system’s acceleration during the crossing (assume the ant stays on ).
Solution
For an ideal Atwood machine, applying Newton’s second law to both masses and recalling that the string tension is equal at both ends, the system’s acceleration is:
The total mass hung from the pulley () stays unchanged during the ant’s crossing: what changes is on which side the small mass sits.
Before the crossing (ant on ): the “light” side weighs , the “heavy” side . The difference is :
After the crossing (ant on ): the light side weighs , the heavy side . The difference rises to :
Percentage change. The difference in acceleration is:
Relative to the initial value:
The effect is surprisingly large: shifting just between the two sides changes the acceleration by . The reason is that what matters is the difference , small compared with the masses involved; a tiny ant switching sides changes this difference by , i.e. about . The system is so sensitive because it operates close to the balance point between the two masses.
Links
Topics: Dynamics Concepts: Newton’s second law Skills: Analysis of limiting cases and science-fiction physics Objects: Atwood machine