Some forces have an associated potential energy: a reservoir of energy tied to the position (or configuration) of bodies. Weight is the most familiar example. Lifting a body costs effort, and that effort is not lost: it is stored as gravitational potential energy, ready to convert back into kinetic energy as soon as the body is dropped.

Principle — Gravitational potential energy

Epot,grav=mgh\ev{E_{\text{pot,grav}} = m\,g\,h} where hh is the height above a chosen reference level.

The delicate point is the reference level: the height hh is not an absolute value, but must be measured relative to a level we choose (the floor, sea level, the edge of a table). Consequently the value of Epot,gravE_{\text{pot,grav}} also depends on the choice of zero. This is not a problem, because in physics what matters is never the absolute value of the potential energy, but only its change between two states: and the difference mghBmghAmgh_B - mgh_A does not depend on where we placed the zero. We can therefore choose the reference in whatever way makes the calculation most convenient.

Climbing Everest on croissants

Mount Everest is h=8849  mh = 8849\;\text{m} high. For an 80  kg80\;\text{kg} person, the gravitational potential energy at the summit is: Epot=809,818849=6,94106  JE_{\text{pot}} = 80 \cdot 9{,}81 \cdot 8849 = 6{,}94 \cdot 10^6\;\text{J} A cream-filled croissant contains about 52000  cal=217360  J52\,000\;\text{cal} = 217\,360\;\text{J}. About 3232 croissants would therefore be needed just for the potential energy, without even accounting for friction, wind, and the fact that the human body has an efficiency of barely 25%25\%!

Topics: Lavoro ed energia Concepts: Energia potenziale gravitazionale · Forze conservative

Related exercises: Problem — Block on an inclined plane with spring (equilibrium and oscillations) · Worked exercise — apple and spring · Problem — Estimating the kinetic energy of a car