A stationary 10kg object explodes into three fragments of masses m1=2, m2=3, m3=5kg. Fragment 1 leaves with velocity v1=(10;0)m/s, fragment 2 with v2=(0;−8)m/s. Find v3 and the energy released in the blast.
Solution
Conservation of p (the object is at rest, ptot=0 before and after), component by component:
m1v1x+m2v2x+m3v3x=0⇒2⋅10+3⋅0+5v3x=0⇒v3x=−4m/sm1v1y+m2v2y+m3v3y=0⇒2⋅0+3⋅(−8)+5v3y=0⇒v3y=+4,8m/sv3=(−4;4,8)m/s
Magnitude: ∣v3∣=42+4,82=39,04≈6,25m/s.
Energy released in the blast = total kinetic energy of the fragments:
Eblast=21m1v12+21m2v22+21m3v32=21⋅2⋅100+21⋅3⋅64+21⋅5⋅39,04Eblast=100+96+97,6≈294JEblast≈294J