There is a very useful result linking the centre of mass to gravitational potential energy: to compute the total Epot,gE_\text{pot,g} of a system — an extended object or a set of several bodies — you just need the height of the centre of mass.

Principle — Potential energy and centre of mass

Epot,g=MtotghCM\ev{E_{\text{pot,g}} = M_{\text{tot}}\,g\,h_{\text{CM}}}

The proof is immediate: the total potential energy is imighi=gimihi\sum_i m_i g h_i = g \sum_i m_i h_i. But imihi=MtothCM\sum_i m_i h_i = M_\text{tot}\, h_\text{CM} by the very definition of the centre of mass (it is its height, multiplied by the total mass). So all the information about the vertical distribution of the masses condenses into a single number, hCMh_\text{CM}.

This enormously simplifies calculations in problems with extended objects or systems of several bodies: instead of summing many mighim_i g h_i terms, you find the height of the centre of gravity and multiply by the total weight. It is particularly handy when a body changes shape — a chain sliding, a rope unrolling — because you only need to track how the centre of gravity drops.

Topics: Centre of mass Concepts: Centre of mass · Gravitational potential energy

Related exercises: Challenge: chain on a table · Worked exercise — The cat on the trolley · Rocket exploding mid-trajectory