Angular momentum is to rotation what momentum is to translation: it measures “how much” a body is rotating about a point, taking into account both its momentum and how far it passes from the point.

Principle — Angular momentum

The angular momentum of a body about a point O is L=r×p=r×(mv)\ev{\vec{L} = \vec{r} \times \vec{p} = \vec{r} \times (m\,\vec{v})}

The cross product r×p\vec{r} \times \vec{p} tells us that three things matter: the momentum p\vec{p}, the distance rr from point O, and the angle between the two. A body moving straight towards point O (or straight away from it) has zero angular momentum about O, because r\vec{r} and p\vec{p} are parallel. Angular momentum is maximum when the motion is perpendicular to the radius, i.e. when the body “goes around” the point.

In two dimensions, with r=(x,y)\vec{r} = (x, y) and p=(px,py)\vec{p} = (p_x, p_y), the cross product has just one component (perpendicular to the plane):

L=xpyypxL = x\,p_y - y\,p_x

Like momentum and kinetic energy, angular momentum depends on the choice of pole O and reference frame — and it is precisely this dependence that makes the decomposition in the next note natural.

Topics: Centre of mass Concepts: Angular momentum · Momentum

Related exercises: The rotating diver · Velocity and momentum of the CM · Finding the masses from the CM