If angular momentum is the analogue of momentum, then there must also be an analogue of impulse: the quantity describing how much angular momentum is transferred. This is angular impulse.

Principle — Angular impulse

The exchange of angular momentum between two systems takes place through angular impulse. For a constant moment: Iang=MΔtI_\text{ang} = M\cdot\Delta t In general, a force F\vec{F} applied for a time Δt\Delta t at a point at distance r\vec{r} from the pole produces: Iang=r×(FΔt)=r×I\vec{I}_\text{ang} = \vec{r}\times(\vec{F}\,\Delta t) = \vec{r}\times\vec{I}

The formula mirrors perfectly the translational impulse theorem I=FΔt=Δp\vec{I} = \vec{F}\,\Delta t = \Delta\vec{p}: here the angular impulse equals the change in angular momentum, Iang=ΔL\vec{I}_\text{ang} = \Delta\vec{L}. The presence of the cross product r×I\vec{r}\times\vec{I} reminds us that what matters is not only how much linear impulse is given, but also where and in which direction: the same impulse I\vec{I} applied far from the pole transfers more angular momentum than when applied close to it.

This is why, to make a door swing quickly, you push it as far as possible from the hinges: for the same force and duration, the larger arm maximises the angular impulse transmitted. Applying the same push near the hinges is nearly useless.

Collegamenti

Argomenti: Dinamica rotazionale Concetti: Momento angolare · Conservazione del momento angolare

Esercizi collegati: Il tuffatore che ruota · Cometa al perielio e all’afelio · Problema — Momento torcente rettangolare e L(t)