Same hinged rod, but now the collision is elastic: the projectile bounces elastically off the end of the rod instead of embedding itself. Only one condition changes, and the whole balance changes with it.

  • Angular momentum about the hinge is conserved (as in case 1, same reason: the hinge’s reaction has zero arm).
  • Momentum is not conserved (as in case 1: there is the hinge’s impulsive reaction).
  • Kinetic energy is conserved: the collision is elastic, Etermica=0E_\text{termica} = 0.

Now there are two unknowns: ω\omega (angular velocity of the rod) and vBv_B (velocity of the projectile after the collision, with sign). So two equations are needed: conservation of LL and of EcinE_\text{cin}.

Angular momentum equation (about the hinge):

mpvAL=mpvBL+Iastacardineωm_p v_A L = m_p v_B L + I_\text{asta}^\text{cardine}\,\omega

with Iastacardine=13ML2=5,33  kgm2I_\text{asta}^\text{cardine} = \tfrac{1}{3}ML^2 = 5{,}33\;\mathrm{kg\,m^2} (only the rod: the projectile no longer embeds itself).

Kinetic energy equation:

12mpvA2=12mpvB2+12Iastacardineω2\tfrac{1}{2}m_p v_A^2 = \tfrac{1}{2}m_p v_B^2 + \tfrac{1}{2}I_\text{asta}^\text{cardine}\,\omega^2

Summary of case 2

Two unknowns (vBv_B, ω\omega), two equations (LL, EcinE_\text{cin}): a quadratic system. It is solved like a generalised 1D elastic collision. As always in elastic collisions, the system has two solutions: the trivial one (no collision, vB=vAv_B = v_A, ω=0\omega = 0) and the physical one.

Why there's no conservation of p\vec{p}

Even in an elastic collision, if the rod is hinged the hinge exerts an impulsive constraint reaction that transmits an external impulse: total momentum is not conserved. You cannot write mpvA=mpvB+somethingm_p v_A = m_p v_B + \text{something}. This is the most treacherous mistake in this problem.

Collegamenti

Argomenti: Dinamica rotazionale Concetti: Conservazione del momento angolare · Urto elastico Competenze: Scelta del polo Oggetti: Asta

Esercizi collegati: Problema — La pattinatrice che si stringe · Esercizio svolto — proiettile contro asta incernierata · Problema — Perché il pattinatore ruota più veloce