When the loop rotates in the magnetic field, the flux through it changes: by Faraday’s law (next chapter) an induced electromotive force Eind\mathcal{E}_\text{ind} is generated which, by Lenz’s law, opposes the imposed current. This is the motor’s back electromotive force (back e.m.f.), denoted Ec\mathcal{E}_c.

In a circuit with generator E\mathcal{E}, total resistance RR and back e.m.f. Ec\mathcal{E}_c, the current is:

i=EEcRi = \frac{\mathcal{E} - \mathcal{E}_c}{R}

The faster the motor spins, the more Ec\mathcal{E}_c grows and the more the current drawn decreases. The energy balance per second is written by multiplying by ii: the input electrical power splits between Joule dissipation and useful mechanical power.

Eipot. elettrica in=Ri2Joule+Ecipot. meccanica out\underbrace{\mathcal{E}\,i}_{\text{pot. elettrica in}} = \underbrace{R\,i^2}_{\text{Joule}} + \underbrace{\mathcal{E}_c\,i}_{\text{pot. meccanica out}}

Principle — Energy balance of the motor

Pel=PJoule+PmeccPmecc=Eci=MtorcωP_\text{el} = P_\text{Joule} + P_\text{mecc} \qquad P_\text{mecc} = \mathcal{E}_c\cdot i = M_\text{torc}\cdot\omega The efficiency is η=Pmecc/Pel=Ec/E\eta = P_\text{mecc}/P_\text{el} = \mathcal{E}_c/\mathcal{E}.

This result has an important practical consequence: with the motor stopped (ω=0\omega = 0, hence Ec=0\mathcal{E}_c = 0) all the electrical power is dissipated as heat, and the current drawn is maximum (i=E/Ri = \mathcal{E}/R). This is the moment of greatest risk of overheating: a motor that is mechanically jammed but still powered can burn out.

Collegamenti

Argomenti: Magnetismo Concetti: Dipolo magnetico · Forza elettromotrice · Effetto Joule

Esercizi collegati: Worked exercise — electric motor under load · Motor and dynamo · Bicycle dynamo