Lorentz force on an electron at 1 T

Problem

An electron moves at $1{,}0\cdot 10^6$ m/s perpendicular to a magnetic field of $1{,}0$ T. Calculate the Lorentz force on it.

Solution

Since velocity and field are perpendicular, the magnitude of the Lorentz force is $F = |q|\,v\,B$:

$F = |q|\,v\,B = 1{,}6\cdot10^{-19}\cdot 1{,}0\cdot10^6\cdot 1{,}0$

$\ev{F = 1{,}6\cdot 10^{-13}\;\text{N}}$

Links

Topics: Magnetism Concepts: Lorentz force