EMF on a moving rod

Problem

A conducting rod of length $\ell = 0{,}30 \ \mathrm{m}$ moves at $v = 5{,}0 \ \mathrm{m/s}$ perpendicular to a field of $B = 0{,}20 \ \mathrm{T}$. Calculate the electromotive force induced between its ends.

Solution

For a moving rod the motional EMF is: $\mathcal{E} = B\,\ell\,v = 0{,}20 \cdot 0{,}30 \cdot 5{,}0 = \ev{0{,}30 \ \mathrm{V}}$

Collegamenti

Argomenti: Electromagnetic induction Concetti: Faraday-Neumann-Lenz law · Electromotive force