An electromagnetic wave carries energy. The quantity that describes its flow is the Poynting vector:

Poynting vector

I=E×Bμ0\ev{\vec{I} = \frac{\vec{E}\times\vec{B}}{\mu_0}}

Its direction is that of propagation of the wave (it coincides with E×B\vec{E}\times\vec{B}), and its magnitude is measured in W/m2\text{W}/\text{m}^2: it is a power per unit area, i.e. the energy crossing, every second, a square metre placed perpendicular to the wave.

Key formula — Intensity

I=EBμ0|\vec{I}| = \frac{|\vec{E}|\,|\vec{B}|}{\mu_0} Time average of a harmonic wave: I=E022cμ0\langle |\vec{I}|\rangle = \frac{E_0^2}{2\,c\,\mu_0}

The factor 1/21/2 in the average comes from the average of cos2\cos^2 over a period (which equals 1/21/2): the instantaneous intensity oscillates, but what a sensor measures is its mean value. Using B0=E0/c|B_0| = E_0/c the average can also be rewritten as I=12ε0cE02\langle I\rangle = \tfrac{1}{2}\varepsilon_0 c\,E_0^2, a very convenient form for problems.

Since intensity is proportional to E02E_0^2, doubling the amplitude of the field quadruples the energy carried: it is the same quadratic dependence that governs all waves. For an isotropic point source, the intensity decreases as 1/r21/r^2 with distance, because the same power is spread over spheres of growing surface area 4πr24\pi r^2.

Topics: Electromagnetic waves Concepts: Poynting vector · Intensity of a wave · Electromagnetic wave

Related exercises: Problem — Which EM wave · Worked exercise — Solar panel · Problem — WiFi intensity at 10 metres