Problem
On Earth sunlight arrives with intensity ; the Earth is from the Sun. (a) What is the Sun’s total luminosity (power radiated in all directions)? (b) At what distance from the Sun’s centre does the radiation pressure equal atmospheric pressure ? (c) At what rate (in kg/s) does the Sun lose mass due to radiation?
Solution
(a) Luminosity of the Sun. Energy spreads over concentric spheres: the intensity at distance is . At the Earth’s distance it equals , so
(b) Distance at which the radiation pressure equals . For complete absorption the radiation pressure is . Setting requires an intensity
From we obtain the distance from the centre:
This distance is still well inside the Sun (the solar radius is about ): the radiation pressure only becomes “atmospheric” at from the centre, roughly the same as the distance between Milan and Naples ().
(c) Mass loss due to radiation. By mass-energy equivalence , every unit of radiated energy corresponds to a mass loss. The power corresponds to a mass-loss rate
About million tonnes per second turned into light: enormous in absolute terms, but negligible compared with the Sun’s total mass ().
Connections
Topics: Electromagnetic waves Concepts: Intensity of a wave · Radiation pressure · Mass-energy equivalence Skills: Fermi estimates