Problem
A conducting bar of mass , length , resistance slides without friction on two parallel horizontal rails, immersed in a uniform magnetic field perpendicular to the plane of the rails. The bar starts from rest with a constant external force applied. Determine: (a) the velocity as a function of time, (b) the terminal velocity, (c) the power dissipated in the resistance at steady state.
Solution
Setup (staged approach). The problem interweaves three laws: Newton’s second law (dynamics), the Faraday-Neumann-Lenz law (induction) and the energy balance. We put them in sequence.
Stage 1 — induction. Moving with velocity , the bar generates an induced electromotive force (Faraday’s law, changing area): The current in the circuit, of resistance , has magnitude:
Stage 2 — dynamics. The current in the field produces a Laplace force which, by Lenz’s law, opposes the motion. Newton’s second law along the rails is: This is a first-order linear differential equation in .
(a) Velocity as a function of time. Setting and integrating with the condition : The velocity grows exponentially and saturates: the same form as the charging of a capacitor.
(b) Terminal velocity. At steady state , hence :
(c) Energy balance at steady state. At constant velocity the acceleration is zero: all the power supplied by the external force is dissipated by the Joule effect in .
The three areas interlock: induction (ch. 18) supplies the current, which feeds into the dynamics (variable force, ch. 2) and determines the velocity as a function of time; conservation of energy (ch. 4) closes the account at steady state. The mathematical structure is the same differential equation that also governs falling with viscous drag.
Links
Topics: Electromagnetic induction · Dynamics · Work and energy Concepts: Faraday-Neumann-Lenz law · Laplace force · Joule effect Skills: Conservation of energy