When a gas pushes a piston of area AA through a distance Δh\Delta h, it does work. Since the force exerted by the gas is Fgas=PgasAF_\text{gas} = P_\text{gas}\cdot A, the work is

Lgas=FgasΔh=PgasAΔh=PgasΔVL_\text{gas} = F_\text{gas}\cdot\Delta h = P_\text{gas}\cdot A\cdot\Delta h = P_\text{gas}\cdot\Delta V

where ΔV=AΔh\Delta V = A\,\Delta h is the change in the gas’s volume. This formula holds when the gas pressure remains constant during the displacement (isobaric process).

Watch the signs

LgasL_\text{gas} is the work done by the gas on the piston.

  • If the piston rises (gas expanding), ΔV>0\Delta V > 0 and Lgas>0L_\text{gas} > 0: the gas gives energy to the environment.
  • If the gas is compressed, ΔV<0\Delta V < 0 and Lgas<0L_\text{gas} < 0: the gas receives energy.

The intuition is that of a push along a displacement: the gas “pushes” the piston outwards, and like any force acting in the direction of the displacement, it does positive work, giving up energy. If instead it is the outside that pushes the piston in, compressing the gas, the work done by the gas is negative and energy enters the gas.

Collegamenti

Argomenti: Teoria cinetica dei gas · Termodinamica Concetti: Pressione · Lavoro di una forza

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