Problem

Two particles (q1=103 Cq_1 = 10^{-3}\ \text{C}, m1=1 kgm_1 = 1\ \text{kg}; q2=104 Cq_2 = -10^{-4}\ \text{C}, m2=2 kgm_2 = 2\ \text{kg}) are initially at a distance d=10 md = 10\ \text{m}. A friction force Fa=5 NF_a = 5\ \text{N} acts between them, dissipative and constant along the path. The charges attract each other: do they meet? Use an energy table with EcinE_{\text{cin}}, Epot,el=kq1q2/rE_{\text{pot,el}} = k\,q_1 q_2/r and EtermE_{\text{term}}; compare the energy released by the approach with the work done by friction.

Topics: Electrostatics Concepts: Electrostatic potential energy · Kinetic energy Skills: Conservation of energy Methods: Energy-exchange bubble diagram