Problem
Two particles (, ; , ) are initially at a distance . A friction force acts between them, dissipative and constant along the path. The charges attract each other: do they meet? Use an energy table with , and ; compare the energy released by the approach with the work done by friction.
Solution
Using . The charges have opposite signs, so they attract and the electrostatic potential energy is negative:
Balance (bubble diagram): the approach releases potential energy (which becomes kinetic energy), while friction dissipates some of it as heat. The charges meet if, as they approach, the potential energy released exceeds the work done by friction.
Potential energy at :
As they approach, decreases and : the energy released is unbounded. Quantitative comparison closing from down to, say, :
Work done by friction over the initial :
Already, closing by just releases ; as they get closer the available energy grows without bound while friction dissipates at most over the whole path. The attraction wins clearly.
Links
Topics: Electrostatics Concepts: Electrostatic potential energy · Kinetic energy Skills: Conservation of energy Methods: Energy-exchange bubble diagram