Problem
For the thermodynamic cycle in the figure (ideal gas, ), identify the phases in which the gas absorbs and releases heat. Estimate the work per cycle as the enclosed area.
Solution
The four phases. The cycle is a rectangle with alternating isobaric sides (constant pressure, horizontal segments) and isochoric sides (constant volume, vertical segments). For an ideal gas , so the temperature is highest at the top-right vertex and lowest at the bottom-left one.
- (isobaric, low , increases): expansion, increases heat absorbed ().
- (isochoric, large , increases): increases heat absorbed ().
- (isobaric, high , decreases): compression, decreases heat released ().
- (isochoric, small , decreases): decreases heat released ().
Work as area. The net work done by the gas in a cycle is the area enclosed in the - plane, with sign given by the direction of travel. The rectangle has base and height :
Sign. The path is anticlockwise (right at the bottom, up on the right, left at the top, down on the left). An anticlockwise cycle in the - plane gives net negative work (work done ON the gas): the gas gives back more work in the high-pressure compression than it receives in the low-pressure expansion. This is a reverse cycle (refrigerator/heat pump), not an engine.
Collegamenti
Argomenti: Thermodynamics Concetti: Thermodynamic transformations · First law of thermodynamics · Ideal gas law Competenze: Solving a thermodynamic cycle · Reading graphs Metodi: P-V and ln P - ln V diagram Oggetti: Ideal gas